Res 342 Week 2. Ex.

9.54 The firm examined 35 randomly chosen fax transmissions during the succeeding(a) year, amenable a sample mean of 14.44 with a specimen leaving of 4.45 pages. (a) At the .01 level of significance, is the straightforward mean greater than 10? Ho: u <= 10 Ha: u > 10 exemplar mean = 14.44 S = 4.45 CX = .01 test statistic: t = 5.7582.. p-value = P(t > 5.9028.. with df=34) = 0.0000005758 (14.44 10 / 4.45 sqrt 35 = 4.45/.7522 = 5.90) Since the p-value is less than 1%, reject Ho. Hypotheses: H0: ? ? 10 Ha: ? > 10 (claim) Critical Value: ? = 0.01, for a one-tailed test, zcrit = 2.236 canvass Value: ztest = (xbar - ?) / [ s/?n ] ztest = (14.44 - 10) / [ 4.45/?35 ] ztest = 5.9027 null opening = rejected analysis: insufficient evidence to support the true mean is greater than 10. 9.62 The Web-based confederation Oh Baby! Gifts has a polish of processing 95 per centum of its orders on the very(prenominal) day they argon receive d. If 485 out of the next 500 orders are processsed on the same day, would this prove that they are exceeding their goal, using a = .

025? Hypotheses: H0: p ? 0.95 Ha: p > 0.95 (claim) Critical Value: ? = 0.025, for a one-tailed test, zcrit = 1.96 N = 500 tt = 0.95 p = 485/500 = .97 x = .025 Z = P tt / sqrt tt (1-tt) / N .97 - .95 sqrt .95 (1-.95)/500 = .02/.009 ? = np = (500)(0.95) = 475 ? = ?npq = ?(0.95)(0.05)(500) = 4.8734 ztest = (X - ?) / ? ztest = (485 - 475) / 4.8734 ztest = 2.06 Decision: ztest > Reject the null hypothesis Summary: Statistics wear outt (prove) anything, they can only p rovide a probability.If you deprivation to ! get a full essay, order it on our website: BestEssayCheap.com

If you want to get a full essay, visit our page: cheap essay